func sequence<T>(_: T, next: @escaping (T) -> T?) Returns a sequence formed from first and repeated lazy applications of next. The first element in the sequence is always first, and each successive element is the result of invoking next with the previous element. The sequence ends when next returns nil. If next never returns nil, the sequence is infinite. This function can be used to replace many cases that were previously handled using C-style for loops. Example: // Walk the elements of a tree from a node up to the root for node in sequence(first: leaf, next: { $0.parent }) { // node is leaf, then leaf.parent, then leaf.parent.parent, etc. } // Iterate over all powers of two (ignoring overflow) for value in sequence(first: 1, next: { $0 * 2 }) { // value is 1, then 2, then 4, then 8, etc. } first: The first element to be returned from the sequence. next: A closure that accepts the previous sequence element and returns the next element. Returns: A sequence that starts with first and continues with every value returned by passing the previous element to next. See Also: sequence(state:next:) Declaration func sequence<T>(first: T, next: @escaping (T) -> T?) -> UnfoldSequence<T, (T?, Bool)> func sequence<T, State>(_: State, next: @escaping (inout State) -> T?) Returns a sequence formed from repeated lazy applications of next to a mutable state. The elements of the sequence are obtained by invoking next with a mutable state. The same state is passed to all invocations of next, so subsequent calls will see any mutations made by previous calls. The sequence ends when next returns nil. If next never returns nil, the sequence is infinite. This function can be used to replace many instances of AnyIterator that wrap a closure. Example: // Interleave two sequences that yield the same element type sequence(state: (false, seq1.makeIterator(), seq2.makeIterator()), next: { iters in iters.0 = !iters.0 return iters.0 ? iters.1.next() : iters.2.next() }) state: The initial state that will be passed to the closure. next: A closure that accepts an inout state and returns the next element of the sequence. Returns: A sequence that yields each successive value from next. See Also: sequence(first:next:) Declaration func sequence<T, State>(state: State, next: @escaping (inout State) -> T?) -> UnfoldSequence<T, State>